$options['where']

You're very close. In PHP variables are only replaced with their values (or "interpolated" as programmer types say) in "double quoted strings". So, basically instead of 'single quotes' use "double quotes" and it will work.

Also, don't forget to escape your variables before you use them in MySQL. Like this:

$escapedVar = escapeMysqlString($var);
$options['where'] = "fieldname = '$escapedVar'";

Hope that helps!

hello, i was reading this post and have the same issue not working i have as follows:

require_once "............viewer_functions.php";
$options = array(); // NOTE: see online documentation for more details on these options
$options['tableName'] = 'vehiculos'; // (REQUIRED) MySQL tablename to list record from. Example: "article";
$options['recordNum'] = '9'; // (optional) Record number to display. Example: "1"; Defaults to number on end of url, then 1
$options['where'] = ''; // (ADVANCED) MySQL WHERE conditions to use INSTEAD of recordNum to look up record. Example: "fieldname = 'value'"
$record = getRecord($options);

would like it to be replaced with a value from another table in mysql so i did this:

require_once "............viewer_functions.php";
$options = array(); // NOTE: see online documentation for more details on these options
$options['tableName'] = 'cajas'; // (REQUIRED) MySQL tablename to list record from. Example: "article";
$options['recordNum'] = '1'; // (optional) Record number to display. Example: "1"; Defaults to number on end of url, then 1
$options['where'] = ''; // (ADVANCED) MySQL WHERE conditions to use INSTEAD of recordNum to look up record. Example: "fieldname = 'value'"
$record = getRecord($options);
$cajita = $record['caja1']; this is to have a value from one table[/#ff0000]
?>
<?php
require_once "............viewer_functions.php";
$options2 = array(); // NOTE: see online documentation for more details on these options
$options2['tableName'] = 'vehiculos'; // (REQUIRED) MySQL tablename to list record from. Example: "article";
$options2['recordNum'] = ''; // (optional) Record number to display. Example: "1"; Defaults to number on end of url, then 1
$escapedVar = escapeMysqlString($cajita);
$options2['where'] = "num[/#ff0000] = '$escapedVar'"; // (ADVANCED) MySQL WHERE conditions to use INSTEAD of recordNum to look up record. Example: "fieldname = 'value'"
$record = getRecord($options);

but for some reason itwont work dispaying $record['num'] as the number in $cajita

any help with this would be great

Hi mawebplus,

Double check your second block of code. If you're calling your options $options2 you want to make sure you're passing that to getRecord as well:

$record = getRecord($options2);

Also, you might want to name your $record variables something else so they don't overwrite each other. For example, $cajasRecord.

Let me know if that helps!