IF image THEN ...

13 posts by 2 authors in: Forums > CMS Builder
Last Post: May 6, 2008 (RSS)

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By Dave - May 2, 2008

Great, glad to hear it's working! For the other it's the same idea:

<td id="sumimg-mainimage">

  <?php $mainImages = getUploads($options['tableName'], 'main_image', $record['num']) as $upload); ?>
  
  <?php foreach ($mainImages as $upload): ?>
    <?php if ($upload['hasThumbnail']): ?>
      <a href="<?php echo $upload['urlPath'] ?>"><img src="<?php echo $upload['thumbUrlPath'] ?>"
       width="<?php echo $upload['thumbWidth'] ?>" height="<?php echo $upload['thumbHeight'] ?>"
       alt="Product Main Image - <?php echo $upload['filename'] ?>" title="<?php echo $record['name'] ?>" /></a>
    <?php endif ?>
  <?php endforeach ?>
  
  <?php if (count($mainImages) == 0): ?>  
      <img src="/images/NoImage-main.jpg" alt="NoImage-main.jpg" />
  <?php endif ?>  

</td>

Let me know if that does it.

Dave Edis - Senior Developer
interactivetools.com

Re: [Dave] IF image THEN ...

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By rasbro - May 6, 2008

Dave, once I discovered this error in the code you gave me...

<?php $mainImages = getUploads($options['tableName'], 'main_image', $record['num']) as $upload); ?>

and changed it to...

<?php $mainImages = getUploads($options['tableName'], 'main_image', $record['num']); ?>

then it worked great.

Thanks!

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By Dave - May 6, 2008

Ahh yes, good eye. That was my mistake. Glad it's working now! :)

Dave Edis - Senior Developer
interactivetools.com