Undefined Variable Error

7 posts by 3 authors in: Forums > CMS Builder
Last Post: May 12, 2011   (RSS)

By dccreatives - May 11, 2011 - edited: May 11, 2011

I have a field called 'mounting' within my section editor called Gallery.

I want to have the page call the mounting in the title of my page.

I inserted this code on the top of the page:

<?php echo $galleryRecord['mounting'] ?> Gallery Images

I am getting the following error: Notice: Undefined variable: galleryRecord in /services/webpages/a/x/axislighting.com/public/CMS/GalleryList.php on line 98 Gallery Images

I used this syntax for most of my pages and I never got an error.

Please advise.

I uploaded the file and here it is online:

http://www.axislighting.com/CMS/GalleryList.php?mounting=pendant

Note: When I put in a foreach statement before the whole table it worked, but then looped my table again and again.

Where should I define the variable that it should not loop?
Attachments:

gallerylist.php 6K

Re: [dccreatives] Undefined Variable Error

By gkornbluth - May 11, 2011

H dccreatives,

It would seem that you will need a foreach loop in order to pull records from a list of records.

You can use a <?php break ?> before the endforeach to stop the looping after the first record.

Hope that gets you going in the right direction.

Best,

Jerry Kornbluth
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Take advantage of a free 3 month trial subscription, only for CMSB users, at: http://www.thecmsbcookbook.com/trial.php

Re: [gkornbluth] Undefined Variable Error

By dccreatives - May 11, 2011

Can you please give me an example of how to use it?

Re: [dccreatives] Undefined Variable Error

By gkornbluth - May 11, 2011

Hi,

Something like

At the top of the page:
// load records
list($galleryRecords, $galleryMetaData) = getRecords(array(
'tableName' => 'gallery',



In your table:
<?php foreach ($galleryRecords as $record): ?>
<?php echo $record['mounting'] ?> Gallery Images
<?php break ?>
<?php endforeach ?>


Good luck,

Jerry Kornbluth
The first CMS Builder reference book is now available on-line!







Take advantage of a free 3 month trial subscription, only for CMSB users, at: http://www.thecmsbcookbook.com/trial.php

Re: [dccreatives] Undefined Variable Error

By Jason - May 11, 2011

Hi,

Another option would be to limit your query to only one result and then put the first record in it's own variable.

For example:
// load records
list($galleryRecords, $galleryMetaData) = getRecords(array(
'tableName' => 'gallery',
'limit' => 1,
));

$galleryRecord = $galleryRecords[0]; // get first record.


You can then use the variable $galleryRecord without needing a foreach loop.

Hope this helps
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Re: [gkornbluth] Undefined Variable Error

By dccreatives - May 12, 2011

Thank You. It worked perfectly.