splitting first image

Hi Locom.

Here's a recipe from my CMSB Cookbook thecmsbcookbook.com that might get you started on working out an answer to your first question. (I'm not sure I understand the second question)

Hope it helps.

Best,

Jerry Kornbluth

COUNTING IMAGES IN A MULTI-IMAGE UPLOAD FIELD

I needed to count the number of images that existed in a multi-image upload field that was the only record in my editor, so that if there was only one image I could display it as an image and if there was more than one image I could display them as a slide show.

I started out with another recipe in the Cookbook called: LIMITING THE NUMBER OF IMAGES ON A PAGE AND SHOWING CODE IF EXCEEDED (just above this one)

The basic approach in that recipe is:
<?php foreach ($home_page_slidesRecords as $record): ?>
<?php $count = 0; ?>
<?php foreach ($record['image'] as $upload): ?>
<?php $count++; ?>
<?php endforeach; ?>
<?php echo $count>1 ? "There is more than one thumbnail" : "There is only one thumbnail" ; ?>
<?php endforeach; ?>
I modified the code so that instead of messages, the required code was inserted into the page. I also added a checkbox field to allow the client to decide if they wanted to use this as a slide show regardless of how many images were uploaded. I also added <?php shuffle($record['images']) ?> to the code to randomize the image displayed when there was no slide show.
<?php foreach ($home_page_slidesRecords as $record): ?>
<?php $count = 0; ?>
<?php foreach ($record['image'] as $upload): ?>
<?php $count++; ?>
<?php endforeach; ?>
<?php if ($count > 1 && $home_page_slidesRecord['slideshow'] == 1): ?>
<div id="show" class="slideshow"></div>
<?php else: ?>
<?php shuffle($record['images']) ?><?php foreach ($record['image'] as $upload): ?><img src="<?PHP echo $upload['thumbUrlPath'] ?>" width="<?PHP echo $upload['thumbWidth'] ?>" height="<?PHP echo $upload['thumbHeight']
?>" alt="" />
<?PHP endforeach ?>
<?php endif ?>
<?php endforeach; ?>

Here's another recipe that might offer some direction. Hope it helps,

Jerry Kornbluth

DISPLAY A SPECIFIC IMAGE FROM A SPECIFIC RECORD

My client wanted to be able to display a specific image from a group of records and multi image uploads.

I couldn’t get this to work until Chris Waddell from Interactive Tools unlocked the secret.

He said:

If $affiliationsRecords is a list of all your records, then $affiliationsRecords[0] will give you the first record, $affiliationsRecords[1]
will give you the second, etc. It's a little confusing that the counting starts at 0 instead of 1.

$affiliationsRecords[3]['logo'][2] will grab the fourth record ([3]), its list of images (['logo']), and select its third image ([2]).

Since $affiliationsRecords[1]['logo'] refers to the list of images. You need to use $affiliationsRecords[1]['logo'][0] if you want to refer
to a specific image ([0] gives you the first one, etc.)

You’ll need to define a variable for the specific image. To call the 3rd image from the 4th record I used

<?php $myImage = $affiliationsRecords[3]['logo'][2]; ?>

The code that you’d use in the body of your viewer page where you want the image to display would be:

<?php $myImage = $affiliationsRecords[3]['logo'][2]; ?>
<img src="<?php echo $myImage['thumbUrlPath'] ?>" width="<?php echo $myImage['thumbWidth'] ?>" height="<?php echo $myImage['thumbHeight']
?>" alt="" />
You can also define other variables, like this one for the link to a detail page relating to the same record:

<?php @$mylink = $affiliationsRecords[4]['_link']; ?>

Then the code including a linked image might look like this:

<?php @$myImage = $affiliationsRecords[3]['logo'][2]; ?>
<?php @$mylink = $affiliationsRecords[3]['_link']; ?>
<a href="<?php echo $mylink ?>"><img src="<?php echo $myImage['thumbUrlPath'] ?>" width="<?php echo $myImage['thumbWidth'] ?>"
height="<?php echo $myImage['thumbHeight'] ?>" alt="" border="0"/></a>