Image Don't Show on Web page

Hi wow123,

Do you mean that the page showed images once, and now that you've changed the upload directory the page doesn't show the images?

Jerry Kornbluth

No,

the place where the image is suppose to be on the web site says this:

Record Number: 1
_link : inventory-detail.php?1
image:

Upload Url: /cmsAdmin/uploads/13.jpg


No Image shows up.
Here is the URL: http://www.seventhwing.com/inventory.php

Hi wow123,

OK, so far I’ve found a few things...

Your detail pages actually has an underscore not a dash. It’s probably mistyped in the section editor detail page URL field.

The code on your detail page is missing a < before ?php header('Content-type: text/html; charset=utf-8'); ?>

I can’t see the php code on your page, but for a link to your detail page the basic code could be something like:
<a href="<?php echo $record['_link'] ?>">the text, image or echoed field that you want to show on your page</a>

So to display an image on your list page that can be clicked on to access the detail page, the code inside your main foreach loop should be something like:

<?php foreach ($record['your_image'] as $upload): ?>
<a href="<?php echo $record[‘_link'] ?>"><img border="0" src="<?php echo $upload['thumbUrlPath'] ?>" width="<?php echo $upload['thumbWidth'] ?>" height="<?php echo $upload['thumbHeight'] ?>" alt="" /></a>
<br />
Title: <?php echo $upload[‘info1'] ?>
<br />
Caption: <?php echo $upload[‘info2'] ?>
<br />
<?php endforeach; ?>

If you did not want to link the image, you could just use:

<?php foreach ($record['your_image'] as $upload): ?>
<img border="0" src="<?php echo $upload['thumbUrlPath'] ?>" width="<?php echo $upload['thumbWidth'] ?>" height="<?php echo $upload['thumbHeight'] ?>" alt="" />
<br />
Title: <?php echo $upload[‘info1'] ?>
<br />
Caption: <?php echo $upload[‘info2'] ?>
<br />
<?php endforeach; ?>


border="0" gets rid of the border around your images that appears in IE.

If you were using this code on a detail page, you would leave off the foreach loops and replace each occurrance of the variable $record with $your_tableRecord.

Hope that helps,

Jerry Kornbluth