Displaying Different name from a "List" field
7 posts by 2 authors in: Forums > CMS Builder
Last Post: November 6, 2012 (RSS)
By efi-revivo - November 1, 2012 - edited: November 1, 2012
When i insert this line; <?php echo htmlspecialchars($vehicleListed) ?> it's show the name only - and I want to show something else.
<?php $vehicleList = getListLabels('listing', 'icons', $listingRecord['icons']) ?>
<?php foreach($vehicleList as $vehicleListed): ?>
<?php if ($listingRecord['icons']): ?>
<img src="icons/<?php echo htmlspecialchars($vehicleListed) ?>.png" alt="Different name (iconhebrew field instead of name)" width="25" height="25" border="0" title="<?php echo htmlspecialchars($vehicleListed) ?>"/>
<?php endif ?>
<?php endforeach ?>Thanks,
Efi
Re: [efi-revivo] Displaying Different name from a "List" field
By Jason - November 1, 2012
Where is the iconhebrew field stored? Is the icons lsit field in ListingRecord being populated by a different section? If so, what is that section called, and what is the list value in then "icons" field?
Let me know and we should be able to put together an example for you.
Thanks
Jason Sauchuk - Project Manager
interactivetools.com
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Re: [Jason] Displaying Different name from a "List" field
iconhebrew stored inside icons table (category section)
under the "name" i insert a new field "iconhebrew"
the listing section use this table for icons in our site
The "name" field is for english and iconhebrew is for hebrew.
Re: [efi-revivo] Displaying Different name from a "List" field
By Jason - November 1, 2012
What field is used for the option value for "icon" in the listing section?
Jason Sauchuk - Project Manager
interactivetools.com
Hire me! Save time by getting our experts to help with your project.
http://www.interactivetools.com/consulting/
Re: [Jason] Displaying Different name from a "List" field
By efi-revivo - November 1, 2012 - edited: November 4, 2012
for field option values i use"name"
for the image name.
and for field option labels i use "iconhebrew"
Thanks,
Efi
Re: [efi-revivo] Displaying Different name from a "List" field
By Jason - November 5, 2012
If the value of $vehicleListed comes from the name field of your icons table, you can retrieve the entire icons record like this:
<?php $vehicleList = getListLabels('listing', 'icons', $listingRecord['icons']) ?>
<?php foreach($vehicleList as $vehicleListed): ?>
<?php if ($listingRecord['icons']): ?>
<?php $iconRecord = mysql_get("icons", null, "name = '".mysql_escape($vehicleListed)."'"); ?>
<img src="icons/<?php echo htmlspecialchars($vehicleListed) ?>.png" alt="<?php echo @$iconRecord['iconhebrew']; ?>" width="25" height="25" border="0" title="<?php echo htmlspecialchars($vehicleListed) ?>"/>
<?php endif ?>
<?php endforeach ?>Please give this a try and let me know if you run into any problems.
Thanks
Jason Sauchuk - Project Manager
interactivetools.com
Hire me! Save time by getting our experts to help with your project.
http://www.interactivetools.com/consulting/
Re: [Jason] Displaying Different name from a "List" field