Include days in date calculation
15 posts by 2 authors in: Forums > CMS Builder
Last Post: January 13, 2015 (RSS)
By Jesus - January 8, 2015
Hi,
I found a post that it uses what I'm looking for, but I need to include days on the formula so, Is it possible to include days on this date calculation?
Here's a link to the original post (from Deborah): http://www.interactivetools.com/forum/forum-topics-create.php?forumNum=791&postNum=2211635
<?php
$today = time() - strtotime($accountsRecord['hire_date']);
$yearsOld = intval($today/60/60/24/7/4.35/12);
$monthsOld = intval($today/60/60/24/7/4.35); ?>
<?php if ($yearsOld < 1):{echo $monthsOld;} ?> months
<?php elseif ($yearsOld == 1):{echo "1 year";} ?>
<?php else: ?><?php echo $yearsOld ?> years
<?php endif ?>
Thanks in advance,
Jesus
By claire - January 9, 2015
Hi there - could you describe exactly what dates you're trying to compare in this case?
Claire Ryan
interactivetools.com
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By Jesus - January 9, 2015
Hi Claire, thanks for your answer.
Here's what I'm trying to do (a very similar thing that Deborah mentioned on the original post).
Job Start Date vs Today
and on my result I need to have:
year(s) / month(s) / day(s)
Ex.
John Doe, 1 year, 2 months and 3 days
Joe Smith, 2 years, 1 month and 1 day
John Garza, 3 years and 3 months
etc.
Thanks,
Jesus
PS
I've the report builder plugin so I'll like to generate the report on the backend using this plugin (which I think its possible)
By claire - January 9, 2015
Okay, the thread you've referenced here deals with front end code, so it may not work as is. I'll see about referring this to someone here who's familiar with the report builder plugin.
Claire Ryan
interactivetools.com
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http://www.interactivetools.com/consulting/
By Jesus - January 9, 2015
Thank you Claire. I hope I can receive some kind of help so I can create the report I'm looking for.
Jesus
By claire - January 12, 2015
Hey, can you copy and paste the current query you're using for Report Builder in this case here?
Claire Ryan
interactivetools.com
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http://www.interactivetools.com/consulting/
By Jesus - January 12, 2015
Hi Claire,
I'm still not using any query as I'm looking for information on how can I create the query. So I got stuck when I saw that post I mentioned and you told me that will not help me for the report builder. So I'm trying to solve this mystery :) and see how can I create it.
As always thanks to you and the team for all the work and support!
Jesus
By claire - January 12, 2015
Okay, I think you'll have to get to grips with some more advanced MySQL queries then. It's actually not too difficult at all!
Take a look at this: http://stackoverflow.com/questions/16871167/mysql-query-extracting-date-group-by-day
The line that's important is this one:
SELECT FROM_UNIXTIME(date,'%Y-%m-%d') AS perday,
FROM data
GROUP BY FROM_UNIXTIME(date,'%Y-%m-%d')
The FROM_UNIXTIME is the important function, as it lets you do some useful date manipulation - in this case, extracting the day from each datetime - and then group the records by the result.
Does that help?
Claire Ryan
interactivetools.com
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http://www.interactivetools.com/consulting/
By Jesus - January 12, 2015
Lets see.... I need to have this report.
Employer name, How much time he/she had working since he entered.
Table name: trabajadores
Start date field: $record['fecha_de_inicio']
Employer name: $record['nombre']
SELECT FROM_UNIXTIME(fecha_de_inicio,'%Y-%m-%d') AS perday,
FROM trabajadores
GROUP BY FROM_UNIXTIME(fecha_de_inicio,'%Y-%m-%d')
Am I heading on the right direction here?
Thanks!
By claire - January 13, 2015
On second thought, this isn't going to do what you need. Try this:
SELECT nombre, fecha_de_inicio, DATEDIFF(NOW(), fecha_de_inicio) as days_employed
FROM trabajadores
GROUP BY nombre
This should give you the employer, start date, and number of days of employment.
Claire Ryan
interactivetools.com
Save time by getting our experts to help with your project.
http://www.interactivetools.com/consulting/