Image from Multi record

Hi,

When you get an array of records with their uploads, your first record in the array is $records[0] and the second will be $records[1] etc.. You can get specific record this way and put wherever you like on the page.

Hope that helps and let me know if you have any questions!

Thanks,

Thank you but where do I put that code? This is the code I have to pull in the image:

<!-- STEP 2a: Display Uploads for field 'summary_image' (Paste this anywhere inside STEP2 to display uploads) -->
        <!-- Upload Fields: extension, thumbFilePath, isImage, hasThumbnail, urlPath, width, height, thumbUrlPath, thumbWidth, thumbHeight, info1, info2, info3, info4, info5 -->
        <?php foreach ($record['summary_image'] as $index => $upload): ?>
          <?php if ($index >= 1) { continue; } // limit uploads shown ?>

          <img src="<?php echo htmlencode($upload['urlPath']) ?>" width="<?php echo $upload['width'] ?>" height="<?php echo $upload['height'] ?>" alt="<?php echo htmlencode($upload['info1']) ?>" />

        <?php endforeach ?>
      <!-- STEP2a: /Display Uploads -->

If you just want to get the first upload of the record, $record['summary_image'][0] is what you need instead of a foreach loop. If this code snippet is for displaying the rest images then the if statement should be if($index < 1).

Do you have a screenshot or example of what you want to accomplish so I can get a better understanding of the question?

Thanks,

Hi, this is still not working so I have reverted the code to what I had without your fix in place, I have attached the page code and the link to view the example is below, the image should be the main image from the top story not the bottom story as it is now.

http://77.68.95.152/~wwwgreatwalstead/latest-news.php

According to your file, the first record of $latest_newsRecords is $latest_newsRecords[0]. After finishing the first foreach loop your $record variable will contain the last element of $latest_newsRecords. So just use $latest_newsRecords[0]['single_image'][0] should give you the first upload of the first record in $latest_newsRecords.

Sorry I still cannot get this to work, I need only one image to show on the page, so ONLY the image from the first record in a different DIV.

Hi,

Did you try using $latest_newsRecords[0]['single_image'][0]? If so what is the error that you are having?

Yes I did, I don't get an error it just doesn't work. Is there anyway you can try it and send me the code, the trouble is I want the image to be in a different area as you can see from the code I sent.

Sure! You can send a support request to support@interactivetools.com with the ftp information and the file and we will take a closer look at the problem!